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9x^2-89x+192=0
a = 9; b = -89; c = +192;
Δ = b2-4ac
Δ = -892-4·9·192
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-89)-\sqrt{1009}}{2*9}=\frac{89-\sqrt{1009}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-89)+\sqrt{1009}}{2*9}=\frac{89+\sqrt{1009}}{18} $
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